Method document
Sample size for a two-sample t-test
How many participants are needed in each of two independent groups to show that their means differ, with chosen significance and power. The usual design for a parallel-group trial with a continuous outcome. Covers unequal allocation, a baseline covariate, clustering, non-adherence and dropout.
https://statwisely.com/methods/means-two-sample/
When to use it
- A randomised trial or comparative study with two independent groups and a continuous outcome.
Not for
- Groups expected to vary very differently, especially with unequal group sizes. Use Welch’s t-test.
- More than two groups. Use one-way ANOVA, or the multi-arm comparison against a shared control.
- Showing that a new treatment is not worse than, or equivalent to, another. Use non-inferiority or equivalence.
Notation
- Participants in groups 1 and 2
- Allocation ratio n₂ / n₁
- Difference between the group means
- Common standard deviation
- Standardised effect, Δ / σ
- Noncentrality of the t distribution
- Significance level: the chance of a false positive
- Power: the chance of detecting the effect if it is real
- Number of tails: 2 for a two-sided test, 1 for one-sided
- Correlation between the outcome and a baseline covariate
- Intracluster correlation coefficient (ICC)
- Average number of participants per cluster
- Coefficient of variation of cluster size
- Clusters per group
- Expected loss of whole clusters
- Share of the treatment arm not taking treatment, and of the control arm receiving it
- Expected dropout, overall or for each arm (q₁, q₂)
Formulas
The smallest n with enough power
Student’s t-test with a pooled standard deviation. When the effect is real its statistic follows a noncentral t distribution, and n₁ is the smallest whole number whose power reaches the target; the lower rejection region is included for a two-sided test [1].
For intuition: the normal approximation
Not what the calculator uses, but it shows that equal groups are the most efficient, and that halving the effect quadruples the sample.
Adjusting for a baseline covariate
Analysing with a baseline measurement as a covariate (ANCOVA) removes the share r_b² of the outcome’s variance the test would otherwise have to overcome. One participant per group is added back for the degree of freedom the covariate uses [3].
Clustering
When participants are recruited or randomised in clusters, observations within a cluster repeat information, and the sample is multiplied by the design effect. With equal clusters (CV = 0) this is 1 + (m − 1)ρ [4, 5].
Few clusters
Optional. A cluster trial is analysed on cluster-level summaries, so its critical values come from t on 2(C − 1) degrees of freedom rather than the normal distribution. With few clusters this costs participants; because C depends on the sample, it is iterated until it settles [6].
Non-adherence and crossover
An intention-to-treat analysis keeps everyone in the arm they were allocated to, so participants who do not receive their allocated treatment dilute the difference. Lachin’s correction restores the power [7].
All adjustments together
The adjustments multiply, in this order, and the result is rounded up once. Any adjustment not used contributes a factor of 1.
Dropout
Applied last, to the participants actually recruited. The rate can differ between the arms; when it does not, q₁ = q₂ = q.
Clusters to recruit
Per group. Losing a whole cluster loses every participant in it, so an expected loss of clusters inflates the clusters recruited rather than the participants.
Parameters
Difference to detect
Values: Not zero, in the measurement’s units
The smallest difference that would matter, clinically or practically. Not the difference you hope for: a study sized for an optimistic effect is underpowered for a real but smaller one.
Standard deviation
Values: Above 0, in the measurement’s units
From a comparable published study, a pooled SD from several studies, or pilot data. The sample size grows with its square, so check a larger value too.
Cohen’s d, instead of the two aboveOptional
Values: Above 0
The difference in standard-deviation units. Cohen’s benchmarks of 0.2, 0.5 and 0.8 for small, medium and large are a last resort; a difference and SD from your own field are better [1].
Significance level
Values: Between 0 and 1; usually 0.05
The false-positive rate you accept. A smaller α, for example to allow for several primary outcomes, needs a larger sample.
Power
Values: Between 0 and 1; usually 0.80 or 0.90
The chance of a significant result if the assumed effect is real. Funders and ethics committees commonly expect at least 0.80.
One- or two-sided
Values: 2 (two-sided) or 1 (one-sided)
Two-sided is the default. A one-sided test is justified only when an effect in the other direction would be treated exactly as no effect, and should be stated in advance.
Allocation ratioOptional
Values: Above 0; 1 for equal groups
The planned size of group 2 divided by group 1. Equal groups need the fewest participants in total; unequal allocation can be worth it when one arm is cheaper or more acceptable.
Expected dropoutOptional
Values: 0% up to, but not including, 100%
The share of participants expected to provide no outcome, from comparable studies. Recruiting more restores the numbers, not the comparability of the groups: if dropout is related to the outcome, the estimate can still be biased.
Dropout in each armOptional
Values: 0% up to, but not including, 100%, for each arm
When dropout is expected to differ between arms, for example higher with an unpleasant treatment. Each arm is then inflated by its own rate.
Baseline correlationOptional
Values: Between −1 and 1
The correlation between the outcome and its baseline measurement, from previous data. Only use it if the analysis will adjust for the baseline.
Intracluster correlation (ICC)Optional
Values: From 0 to 1
For clustered designs only. Published ICCs for health outcomes in primary-care and community clusters are mostly small, often below 0.05 [8]; prefer an estimate from a comparable trial.
Average cluster sizeOptional
Values: At least 1
The average number of participants per cluster. Given with the ICC.
Variation in cluster sizeOptional
Values: 0 or more; 0 for equal clusters
The SD of cluster sizes divided by their mean. Unequal clusters cost power on their own account [5].
Expected loss of whole clustersOptional
Values: 0% up to, but not including, 100%
Clusters, such as practices or schools, expected to withdraw entirely.
Correction for few clustersOptional
Values: On or off
Worth applying when there are few clusters per group, roughly fewer than 15–20.
Non-adherence and crossoverOptional
Values: 0% up to, but not including, 100%; the two together below 100%
The share of the treatment arm expected not to take it, and of the control arm expected to receive it, from comparable trials.
Assumptions
- The groups are independent, and participants are independent of one another apart from any clustering specified.
- The outcome is roughly normal in each group with the same standard deviation. With unequal spread, and especially unequal group sizes, use Welch’s test.
- With clustering: clusters are independent, with the same ICC throughout, and the analysis accounts for the clustering, for example with a mixed model or cluster-level summaries [4].
- Dropout is unrelated to the outcome; recruiting more participants restores the numbers but cannot remove bias.
- Non-adherence is corrected for an intention-to-treat analysis, with treatment received having its full effect and no effect otherwise.
Worked examples
Two equal groups
Difference 5, SD 10, so d = 0.5; α = 0.05 two-sided, 80% power: 64 per group, 128 in total.
Group 1: 64 · Group 2: 64 · Total: 128
Open this example in the calculatorProtocol statement
To detect a difference in means of 5 with 80% power at a two-sided significance level of 0.05, using a two-sample t-test, and assuming a standard deviation of 10, the required sample size is 64 per group (128 in total). Calculated with StatWisely (statwisely.com) using: n₁ and n₂: solve noncentral-t power for d, α, 1-β, and allocation ratio. These are planning estimates; confirm the final design with a qualified statistician.
Twice as many in group 2
With a 1 : 2 allocation, 48 and 96: 144 in total, against 128 with equal groups.
Group 1: 48 · Group 2: 96 · Total: 144
Open this example in the calculatorAdjusting for the baseline
With a baseline correlation of 0.5: 64 × (1 − 0.5²) = 48, plus 1 for the covariate, so 49 per group.
Group 1: 49 · Group 2: 49 · Total: 98
Open this example in the calculatorProtocol statement
To detect a difference in means of 5 with 80% power at a two-sided significance level of 0.05, using a two-sample t-test, and assuming a standard deviation of 10, the test itself needs 64 per group. With adjustment for a baseline covariate (r = 0.5), the required sample size is 49 per group (98 in total). Calculated with StatWisely (statwisely.com) using: n₁ and n₂: solve noncentral-t power for d, α, 1-β, and allocation ratio; ANCOVA: n x (1 - r^2) + 1. These are planning estimates; confirm the final design with a qualified statistician.
A cluster-randomised trial
Clusters of 10 with ICC 0.05: DE = 1 + 9 × 0.05 = 1.45, so 64 × 1.45 = 92.8, rounded up to 93 per group, in 10 clusters per group.
Group 1: 93 · Group 2: 93 · Total: 186
Open this example in the calculatorProtocol statement
To detect a difference in means of 5 with 80% power at a two-sided significance level of 0.05, using a two-sample t-test, and assuming a standard deviation of 10, the test itself needs 64 per group. With clustering (ICC 0.05, an average of 10 per cluster; design effect 1.45), the required sample size is 93 per group (186 in total), in 10 clusters per group. Calculated with StatWisely (statwisely.com) using: n₁ and n₂: solve noncentral-t power for d, α, 1-β, and allocation ratio; clustered: n x DE, DE = 1 + (m-1)ρ. These are planning estimates; confirm the final design with a qualified statistician.
Allowing for non-adherence
If 10% of the treatment arm will not take it and 5% of the control arm will: 64 / (1 − 0.10 − 0.05)² = 88.6, so 89 per group.
Group 1: 89 · Group 2: 89 · Total: 178
Open this example in the calculatorProtocol statement
To detect a difference in means of 5 with 80% power at a two-sided significance level of 0.05, using a two-sample t-test, and assuming a standard deviation of 10, the test itself needs 64 per group. With non-adherence of 10% in the treatment arm and crossover of 5% in the control arm, the required sample size is 89 per group (178 in total). Calculated with StatWisely (statwisely.com) using: n₁ and n₂: solve noncentral-t power for d, α, 1-β, and allocation ratio; non-adherence: n / (1 - d_t - d_c)^2. These are planning estimates; confirm the final design with a qualified statistician.
Different dropout in each arm
Expecting 20% dropout in group 1 and 10% in group 2: 64 / 0.8 = 80 and 64 / 0.9 = 71.1, so 80 and 72 are recruited.
Group 1: 64 · Group 2: 64 · Total: 128 · To recruit: 80 and 72
Open this example in the calculatorProtocol statement
To detect a difference in means of 5 with 80% power at a two-sided significance level of 0.05, using a two-sample t-test, and assuming a standard deviation of 10, the required sample size is 64 per group (128 in total). Allowing for dropout of 20% in the first group and 10% in the second, 80 in the first group and 72 in the second group (152 in total) should be recruited. Calculated with StatWisely (statwisely.com) using: n₁ and n₂: solve noncentral-t power for d, α, 1-β, and allocation ratio. These are planning estimates; confirm the final design with a qualified statistician.
Validation
- Every worked example on this page is recomputed by the StatWisely engine whenever the software is built. If a number or formula here stopped matching the calculator, the release would be stopped until this document was corrected.
- An independent implementation in R recomputes this test every night and before each production release, and the results are compared with the engine’s.
- The basic result agrees with G*Power’s two-sample t-test: 64 per group for d = 0.5, α = 0.05 two-sided and 80% power [2].
How to cite
StatWisely. Sample size for a two-sample t-test. Method document, engine version 1.0.0, reviewed 2026-10-01. https://statwisely.com/methods/means-two-sample/
Cite the original references for the formulas your design uses as well.
References
- 1.Cohen J. Statistical Power Analysis for the Behavioral Sciences. 2nd ed. Hillsdale, NJ: Lawrence Erlbaum Associates; 1988.
- 2.Faul F, Erdfelder E, Lang AG, Buchner A. G*Power 3: a flexible statistical power analysis program for the social, behavioral, and biomedical sciences. Behavior Research Methods. 2007;39(2):175–191.
- 3.Borm GF, Fransen J, Lemmens WAJG. A simple sample size formula for analysis of covariance in randomized clinical trials. Journal of Clinical Epidemiology. 2007;60(12):1234–1238.
- 4.Donner A, Klar N. Design and Analysis of Cluster Randomization Trials in Health Research. London: Arnold; 2000.
- 5.Eldridge SM, Ashby D, Kerry S. Sample size for cluster randomized trials: effect of coefficient of variation of cluster size and analysis method. International Journal of Epidemiology. 2006;35(5):1292–1300. doi:10.1093/ije/dyl129
- 6.Hayes RJ, Moulton LH. Cluster Randomised Trials. 2nd ed. Boca Raton: CRC Press; 2017.
- 7.Lachin JM. Biostatistical Methods: The Assessment of Relative Risks. New York: John Wiley & Sons; 2000.
- 8.Adams G, Gulliford MC, Ukoumunne OC, Eldridge S, Chinn S, Campbell MJ. Patterns of intra-cluster correlation from primary care research to inform study design and analysis. Journal of Clinical Epidemiology. 2004;57(8):785–794. doi:10.1016/j.jclinepi.2003.12.013